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Posted: Wed Aug 01, 2007 3:33 pm Post subject: Question 44 |
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| how are 1 and 2 meso compounds???thanks |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2176
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Posted: Mon Aug 06, 2007 9:13 pm Post subject: |
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In order to see how 1 and 2 become meso: (1) remember that the question says that the C=O group at the top will be oxidized to -COOH (same group at the "bottom" of the molecule in the diagram); (2) keep in mind the definition of a meso compound:
| Quote: | | A meso compound or meso isomer is a chemical compound with molecules that contain 2 or more asymmetric atoms (stereocenters) but which is optically inactive (or achiral) because it contains an internal plane of symmetry. |
http://en.wikipedia.org/wiki/Meso_compound
(3) draw the 2 molecules and you will be able to draw a line (horizontal) that cuts the molecule in 2 parts which are mirror images of each other. |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2176
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Posted: Thu Jul 30, 2009 3:49 pm Post subject: |
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sbains3528
Joined: 16 Aug 2010 Posts: 14
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Posted: Wed Sep 01, 2010 2:36 pm Post subject: |
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| If 1 and 2 become COOH groups why don't 3 and 4? |
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mohsinalam5969
Joined: 18 Apr 2011 Posts: 50
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Posted: Tue Jun 21, 2011 11:55 am Post subject: |
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A meso compound or meso isomer is a chemical compound with molecules that contain 2 or more asymmetric atoms (stereocenters) but which is optically inactive (or achiral) because it contains an internal plane of symmetry.
Also a meso compound or meso isomer is a non-optically active member of a set of stereoisomers, at least two of which are optically active. This means that despite containing two or more stereocenters (chiral centers) it is not chiral. A meso compound is superposable on its mirror image, and it does not produce a "(+)" or "(-)" reading when analyzed with a polarimeter.presence of chiral centre is not compulsory for mesocompounds.
After such oxidation, compounds 1 and 2 become meso compounds and thus non-chiral. Thus they lose their optical activity. However, compounds 3 and 4, after such an oxidation, are still chiral and therefore optically active. |
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sanji2896161
Joined: 23 Oct 2010 Posts: 14
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Posted: Fri Aug 05, 2011 2:18 pm Post subject: |
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| sbains3528 wrote: | | If 1 and 2 become COOH groups why don't 3 and 4? |
a compound with 2 carboxylic acid and an aldehyde functionality would probably be called something other than dicarboxylic acid...seems to be the only hint in the ques |
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mananbhatt3019
Joined: 26 Jun 2011 Posts: 5
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Posted: Sun Aug 07, 2011 3:46 pm Post subject: |
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| 3 and 4's COH's are oxidized to COOH's as well. They are optically active though. If you draw the Fischer projection of the mirror image of either 3 or 4, there is no way to rotate the projection so that it matches the original compound. Thus, they are enantiomers. |
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