mcat_premed3832
Joined: 19 Oct 2006
Posts: 428
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 Posted: Fri Oct 02, 2009 1:00 pm Post subject: |
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It is true that there are few problems on the real MCAT that requires detailed calculations. But it does happen occasionally and regularly. The calculation for this problem is not complex and estimates can be done without consequence:
L/g = .537 m / 1.67 = 1/3 (approx)
Tm = (2/root 3) pi
For the MCAT, you are expected to memorize root 3 (1.7) and root 2 (1.4):
Tm = 1.15 x 3.14 = 3.6
From the Table, we get the equivalent TE = 1.54
Tm - TE = 2.1 seconds
NB: the calculation can be made even faster if you know the results of the sides of a right angle triangle. You would recognize that the inverse of (root 3/2) which is .866. Thus you would have skipped one step above:
Tm = 3.14/.87 = 3.6 |
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