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jimmytech3124
Joined: 07 Apr 2008 Posts: 6
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Posted: Thu Apr 24, 2008 1:52 pm Post subject: Question 22 |
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Hi guys,i am having trouble with this question below. I am having trouble understanding what it means by just "begin" the precipitation (i know what precipitation means). The solution uses ksp of ZnS and finds the concentration of S^2- required to begin percipitation. I would really appriciate if somone could help. Thanks in advance
If in a solution containing only Zn2+, the concentration of zinc ions is 5.0 x 10-3 M, what concentration of S2- is required to just begin the precipitation of zinc sulfide?
5.0 x 10-24 M[x]
2.0 x 10-19 M[x]
3.2 x 10-11 M[x]
5.0 x 10-3 M[x] |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2176
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Posted: Fri Apr 25, 2008 10:37 pm Post subject: |
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To begin with, there is no difference with the concentration required to begin precipitation and the minimum concentration required to produce a precipitation. The key idea is that the solubility product equilibrium constant Ksp allows one to calculate the maximum amount of product which is soluble. If you add one atom more then it results in a precipitate. Thus you can calculate the relevant concentration using the Ksp expression as described in the Explanation (which is cross-referenced to The Gold Standard MCAT text or you can read further using the link below):
http://dbhs.wvusd.k12.ca.us/webdocs/Equilibrium/Writing-Ksp-expression.html |
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jimmytech3124
Joined: 07 Apr 2008 Posts: 6
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Posted: Tue Apr 29, 2008 11:26 am Post subject: |
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Thank you for the explanation, i appriciate your help  |
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starter15
Joined: 28 Dec 2009 Posts: 1
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Posted: Tue Mar 09, 2010 10:53 pm Post subject: |
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I answered D because I thought the concentrations where 1:1 being that that's what the equilibrium expression for dissociation showed. Guess not.
I'll just always use the Ksp values and always know they are for all atom combinations of salts of that particular kind. |
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