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asfino12217
Joined: 13 Aug 2008
Posts: 17
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 Posted: Mon Aug 25, 2008 11:34 am Post subject: Question 31 |
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KE = (1/2)mv2 = kT
What is the k in this equation? |
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nedaa.asba6809
Joined: 04 May 2009
Posts: 36
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| Posted: Fri Jul 17, 2009 12:40 pm Post subject: |
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| In the above equation, k is the Boltzmann constant, and T is the temperature measured in an absolute scale (i.e. the Kelvin scale). |
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quadalpha
Joined: 21 Feb 2010
Posts: 65
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| Posted: Sun Mar 21, 2010 5:51 pm Post subject: |
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| Maybe the second statement should make it clear that KE/temperature is held constant? |
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hua8986059
Joined: 10 Mar 2011
Posts: 55
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| Posted: Thu May 05, 2011 3:30 pm Post subject: |
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actually its KE = 3/2 KT for molecule
KE = 3/2 RT per mole. |
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mohsinalam5969
Joined: 18 Apr 2011
Posts: 50
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| Posted: Sun Jun 19, 2011 2:03 pm Post subject: |
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@asfino
"k" is the boltzman constant while "T" is the temperature in kelvin....
@quadalpha
(1/2)m*(v^2) = (3/2)*K*T
and we know that
PV=nRT................(i)
and we also know that
PV=(2/3)K.............(ii)
so putting value of PV from eq(i) into eq (ii)
RT=(2/3)K
&
3RT/2=K |
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