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rsonia167876
Joined: 12 Jan 2009 Posts: 8
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Posted: Wed Jan 14, 2009 9:40 am Post subject: GS-1 Physical Sciences Question 32 |
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| I am confused about 32, since in 31 we find that collision is inelastic. Then the final velocity of the car and truck should be the same? 3? Since we are told in the passage that after the collision the car moves with the velocity of 3. Very confuse pleae help! |
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JerryWTu7580
Joined: 15 Jan 2009 Posts: 7
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Posted: Fri Jan 16, 2009 3:26 pm Post subject: |
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| In a "completely" inelastic collision, the cars would stick together and the final velocity would be the same. But the problem only says that the collision is inelastic, meaning some energy is lost as heat/crumpling/etc. I hope that helps. |
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rsonia167876
Joined: 12 Jan 2009 Posts: 8
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Posted: Sun Jan 18, 2009 10:29 am Post subject: |
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| Thank you Jerry, it make sense now. |
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nedaa.asba6809
Joined: 04 May 2009 Posts: 36
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Posted: Mon May 04, 2009 2:11 pm Post subject: |
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| Since both objects move in different directions after the collision (not as one mass), the truck will have a different change in velocity than the car and by using the conservation of momentum we can calculate the truck's new velocity. |
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ozairmh8911
Joined: 22 May 2010 Posts: 8
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Posted: Tue May 25, 2010 1:26 pm Post subject: |
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| Is there a quick way to do this question without calculation? |
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jellywing_2058
Joined: 04 May 2009 Posts: 179
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Posted: Thu May 27, 2010 12:47 pm Post subject: |
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| No, you need to use the formula. |
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Berman878951
Joined: 22 Jul 2010 Posts: 3
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Posted: Tue Jul 27, 2010 1:57 pm Post subject: |
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Actually, there is a much simpler way to do this problem without any calculations.
Using physical intuition, this is an easy problem.
Both the car and truck are initially moving in the same direction. Once the car rear-ends the truck, the truck is going to gain some speed. Now let's look at the answer choices:
We can immediately cross out 1.1 m/s as the truck is obviously not going to slow down.
We can also cancel out 3 m/s because the truck must gain some speed. It was just rear-ended by a 1200kg car.
We can also cross out 7.5 m/s because there is no way that the car (which is light compared to the truck) would be able to make the truck gain 4.5 m/s and assume the same speed as the car was initially traveling.
After using the process of elimination, we can confidently chose 3.7 m/s -- meaning that the truck speeds up a little bit after the rear impact.
Hope that helps. |
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