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balak502987
Joined: 08 Jan 2008 Posts: 4
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Posted: Sat Mar 15, 2008 8:30 am Post subject: GS-1 Physical Sciences Question 18 |
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| Since light is entering from the air into the water and being refracted on the surface, wouldn't the equation be 1(sin theta) = 1.333sin(90). solving for sin theta, i get 1.333. How is the answer the inverse of that. Thanks! |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2176
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Posted: Mon Mar 17, 2008 6:39 pm Post subject: |
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The equation cannot be:
1(sin theta) = 1.333sin(90)
because that would suggest that
(sin theta) = 1.333
but of course sine of any angle can never be greater than 1.
The question did not that the "light is entering from the air into the water" since that could never produce a critical angle; the question said the opposite. |
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kimmyb2201994
Joined: 25 Jul 2010 Posts: 2
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Posted: Mon Jul 26, 2010 2:44 pm Post subject: question 18 |
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| The answer key states that "sin θc = 1.00/1.33 ≈ 1/(4/3) = 3/4 = 0.75." And then proceeds to say that means that answer B= .75 is correct. However, sinθc= 0.75, not θc=.75. Is this a mistake of the answer key? shouldn't the answer be in terms of a fraction of pi if we're dealing with radians, or degrees of angles? |
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dnpgr16513
Joined: 14 Jun 2010 Posts: 75
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Posted: Tue Aug 03, 2010 3:19 pm Post subject: |
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| I agree with the person above. |
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jellywing_2058
Joined: 04 May 2009 Posts: 179
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Posted: Mon Aug 09, 2010 2:48 pm Post subject: |
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The question asks:
| Quote: | | What is the value of the sine of this angle when the ray moves from water towards air? |
So as the explanation says, the sin of theta is 0.75, making answer choice B correct. |
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