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Question 5

 
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tingyushih6929



Joined: 11 Jul 2010
Posts: 1

PostPosted: Tue Jul 20, 2010 2:56 pm    Post subject: GS-9 - Physical Sciences #5 Reply with quote

Why is it that at delta G=0 the protein denature??
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jellywing_2058



Joined: 04 May 2009
Posts: 179

PostPosted: Wed Jul 21, 2010 2:11 pm    Post subject: Reply with quote

delta G = 0 means that equilibrium is maintained. If the enzyme no longer is in an equilibrium state, then it would get denatured.
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dnpgr16513



Joined: 14 Jun 2010
Posts: 75

PostPosted: Thu Jul 29, 2010 6:54 pm    Post subject: Reply with quote

Hi,

I'm still confused as to why delta G has to be zero. If it's in equilibrium, then denaturing doesn't occur, right? I thought if Delta G was negative ( which means it's spontaneous) then denaturing would occur. Can someone clarify this?

Thanks!
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harrington5609



Joined: 10 Apr 2010
Posts: 8

PostPosted: Wed Aug 25, 2010 6:39 am    Post subject: Reply with quote

I think what it means is that when delta G = 0, the protein will still denature because of equilibrium conditions, so what's the minimum temperature that will make the entropy x temp part of the equation equal to the enthalpy? If multiplying these two is not greater than 175,000 J, the reaction will be spontaneous due to a negative detal G. If it's greater than 175,000, than it will obviously be non spontaneous since detal G will be positive (no denatured protein).
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