| View previous topic :: View next topic |
| Author |
Message |
Guest
Guest
|
 Posted: Thu May 03, 2007 2:18 pm Post subject: Question 31 |
 |
|
| Can you please explain how you get the new velocity as 0.5/0.6 * 6? Thanks. |
|
| Back to top |
|
 |
admin
Site Admin
Joined: 08 Dec 2003
Posts: 2168
|
| Posted: Fri May 04, 2007 1:15 am Post subject: |
|
|
To calculate the new velocity vf:
Conservation of Momentum
mv = (m + 0.1)vf
where v = 6 m/s is speed of mass m before collision, and vf the speed of the merged mass after collision, m = 0.5 kg (given in the passage).
thus vf = m (0.5/0.6) |
|
| Back to top |
|
|
jsfkt78927
Joined: 06 Jul 2010
Posts: 39
|
| Posted: Tue Jul 27, 2010 2:31 pm Post subject: |
|
|
got this one right!
but still disappointed bc all the questions from this passage were calculation based.....sigh.... does gs know that mcat is mainly conceptual? |
|
| Back to top |
|
|
sanji2896161
Joined: 23 Oct 2010
Posts: 14
|
| Posted: Tue Aug 02, 2011 8:19 pm Post subject: |
|
|
| I THOUGHT MOMENTUM IS NOT CONSERVED IN OSCILLATION BECAUSE A NET EXTERNAL FORCE IS ACTING ON THE OBJECT...the velocity is changing....PLEASE EXPLAIN |
|
| Back to top |
|
|
|
FAQ
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
