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admin Site Admin
Joined: 08 Dec 2003 Posts: 2168
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Posted: Wed Jul 11, 2007 3:10 am Post subject: |
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The calculation is correct.
| Quote: | | 3/4 of the height is submerged, not 3/4 of the total mass of the ball. |
Agreed, that it is not directly related to mass but it is related to density. To be more specific, specific gravity is equal to the fraction of the height of a buoyant object below the surface of the fluid. Thus if SG = 0.70, then 70% of the height of the object would be immersed in the fluid (this use of SG is commonly tested on the real MCAT). |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2168
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Posted: Fri Jul 13, 2007 5:26 pm Post subject: Archimedes Principle and Specific Gravity |
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No, you're not missing something, the physics you used is good.
It is true that normally on the MCAT the object immersed is a block. That way, the rule of thumb regarding SG being the fraction of the height submerged is precise. However, given your approximations, you have shown that it is also a reasonable approximation even if the shape is a sphere (the answer being 0.63 g/cc vs 0.67 g/cc with no answer choices even close).
For those who wish to see the proof regarding a block or cube:
Let h = the height of the block
Let x = the height of the block above the surface of the fluid
Let A = the area of the bottom surface of the block
The volume of displaced water is the volume of the object beneath the surface of the water:
V = (h - x) A
As you mentioned, according to Archimedes' principle, the upward buoyant force on the block is the weight of the water displaced:
Fb = W(water) = D(water)g(h - x)A
where D(water) is the density of water. This must balance the weight W of the block:
Fb = W = DgAh
where D is the density of the block. Thus:
D(water)g(h - x)A = DgAh
Cancel "g" and "A" on both sides and rearrange the equation. Now we have the fractional height of the block above the surface of water given by:
x/h = 1 - SG
where SG = D/D(water)
This link below does not have the proof as above but it has an example of its use:
http://webspinners.com/dlblanc/tectonic/floating.php |
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dnpgr16513
Joined: 14 Jun 2010 Posts: 73
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Posted: Thu Jul 08, 2010 4:19 pm Post subject: |
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Why do you flip 3/4 to 4/3? Please help me!
THANKS |
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jellywing_2058
Joined: 04 May 2009 Posts: 177
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Posted: Mon Jul 12, 2010 1:25 pm Post subject: |
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This is basic math. See the following:
ρball/ρl = 3/4
ρl/pball = 4/3
pl = pball (4/3)
pl = 0.5 g/cm3 x 4/3
pl = 1/2 g/cm3 x 4/3
pl = 2/3 g/cm3
pl = 0.67 g/cm3. |
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dnpgr16513
Joined: 14 Jun 2010 Posts: 73
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Posted: Mon Jul 12, 2010 2:58 pm Post subject: |
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| Ok, great! That's not too bad.. |
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hua8986059
Joined: 10 Mar 2011 Posts: 49
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Posted: Mon Apr 25, 2011 5:54 pm Post subject: |
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| I've noticed that the stuff that MCAT likes to stress are the stuff that actually are very medically applicable. I worked at a cardiologist convention where they talked about ideal fluid flow etc... good stuff to learn |
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