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yfangl097543
Joined: 22 Jun 2007 Posts: 25
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Posted: Wed Jul 18, 2007 12:07 am Post subject: Question 28 |
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| What is the definition of electron affinity? Is it the energy release when an electron is acquired or the energy required to add an electron? |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2176
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Posted: Wed Jul 18, 2007 8:10 pm Post subject: |
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Electron affinity is the energy required to remove an electron from a singly charged negative ion, i.e., the change in E for:
X- --> X + e-
The other definition is that electron affinity is the energy released (Einitial - Efinal) when an electron is attached to a neutral atom or molecule. The sign convention for electron aff. is the opposite to most thermodynamic quantities: a positive electron aff. indicates that energy is released when going from atom to anion.
Last edited by admin on Thu Jul 19, 2007 2:02 pm; edited 1 time in total |
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yfangl097543
Joined: 22 Jun 2007 Posts: 25
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Posted: Wed Jul 18, 2007 9:42 pm Post subject: |
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So in the question:
Why does potassium possess a higher first electron affinity than first ionization energy?
Is it saying that more energy is released when adding an electron to potassium than taking one off? This doesn't make sense... |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2176
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Posted: Thu Jul 19, 2007 5:07 pm Post subject: |
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I think that you would agree that according to the periodic table, K has a very low IE.
So the question is: is it true that its EA is high?
Let's check. We can use either definition of EA, but to be most precise, let's use the second definition.
| Quote: | | The other definition is that electron affinity is the energy released (Einitial - Efinal) when an electron is attached to a neutral atom or molecule. |
Thus we are looking at:
K + e- --> K-
clearly this reaction would require an incredible amount of energy (K- being unstable, very difficult to make). Thus EA >> IE for K. |
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yfangl097543
Joined: 22 Jun 2007 Posts: 25
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Posted: Fri Jul 20, 2007 12:58 pm Post subject: |
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| So wouldn't the electron affinity be negative then, since you would have to INPUT energy, which means no energy is released when K goes to K-? |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2176
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Posted: Sun Jul 22, 2007 5:18 am Post subject: |
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According to the reference below, EA for the reaction in question is positive:
K + e- --> K-
| Quote: | Electron Affinity
An atom's electron affinity is the energy change in an atom when that atom gains an electron. The sign of the electron affinity can be confusing. When an atom gains an electron and becomes more stable, its potential energy decreases: upon gaining an electron the atom gives off energy and the electron affinity is negative. When an atom becomes less stable upon gaining an electron, its potential energy increases, which implies that the atom gains energy as it acquires the electron. In such a case, the atom's electron affinity is positive. An atom with a negative electron affinity is far more likely to gain electrons. |
www.sparknotes.com/chemistry/fundamentals/atomicstructure/section3.rhtml |
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anon3543
Joined: 12 May 2007 Posts: 16
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Posted: Fri Jul 27, 2007 11:09 am Post subject: |
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| I think the REVERSE of "a positive electron aff. indicates that energy is released when going from atom to anion." is true, then everything makes sense... I understand that the positive/negative stuff is only a convention really, but according to everything else you (admin) said, it would be much better to assign release of energy as negative electron affinity. Anyways, that's just my thoughts. |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2176
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Posted: Thu Jul 30, 2009 3:35 pm Post subject: |
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| Bump. |
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mohsinalam5969
Joined: 18 Apr 2011 Posts: 50
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Posted: Tue Jun 21, 2011 11:12 am Post subject: |
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DEFINITION :
The term ionization energy of an atom or molecule means the energy needed to remove electrons from an atom
(Ionization energy is the enery it takes to lose an electron) In K, the electrons are relatively near the positive nucleus..
DEFINITION :
The Electron affinity of a molecule or atom is the energy change when an electron is added to the neutral atom to form a negative ion. This property can only be measured in an atom in gaseous state.
X + eā ā X- ...
hey represent the energy involved in the same process, just reversed.
K+ + e- --> K for the electron affinity of potassium cation
K --> K+ + e- for the ionization energy of potassium metal
My thought is that the energy is same but with opposite signs.
I believe technically you could invoke the law of microscopic reversibility or the quantization of electronic states... but that's probably more complicated than necessary.
But if we have to prove that tha first electron affinity is greater than the ionization energy then there is no other reson except this as given below
Since potassium only has one electron in its outer shell, it is easily removed (i.e. low first ionization potential/energy), thus leaving potassium with the more stable noble gas-like configuration (i.e. Ar). On the other hand, adding an electron to neutral potassium would require much energy (i.e. high first electron affinity) which would leave potassium with two valence electrons which would not be stable.
THANKS |
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