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admin Site Admin
Joined: 08 Dec 2003 Posts: 2168
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Posted: Sat Jul 26, 2008 5:28 pm Post subject: |
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The equations are:
F = T - m1g = m1a
and
F = T - m2g = -m2a
There are several ways to solve these simultaneous equations.
Option 1: subtract one equation from the other in order to eliminate T (as mentioned in the book)
T - m1g = m1a
-(T - m2g = -m2a)
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-m1g + m2g = m1a + m2a
now isolate for a by dividing both sides by (m1 + m2) |
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pszopa1343
Joined: 05 Apr 2010 Posts: 6
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Posted: Sat Jul 10, 2010 11:09 am Post subject: |
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I'm having trouble solving for the Tension. The book doesn't show the work getting to the equation
T = g(2m1m2)/(m1+m2)
Any help with this one?
Thx. |
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DLBMCAT
Joined: 19 Jul 2006 Posts: 12
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Posted: Sun Aug 22, 2010 2:02 pm Post subject: |
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| Can anyone help and isolate for T? |
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jono6411
Joined: 23 Jun 2010 Posts: 1
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Posted: Sun Aug 22, 2010 11:16 pm Post subject: @DLBMCAT |
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Solve for a in the two eq's given by the admin, set them equal to each other, and solve for T.
T=m1a+m1g -> T-m1g=m1a -> T/m1-g=a
T=m2g-m2a -> T-m2g=-m2a -> -(T/m2)+g=a
T/m1-g=-(T/m2)+g -> T(m1+m2)/(m1m2)=2g -> T= 2g(m1m2)/(m1+m2) |
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