Question 31

[stoneprod7112]

I appreciate the explanation butstill don't understand why sigmoidal would not work since it does increase until it levels off which does seem to go along with the explanation. Is there more to the expodential increase pattern of a hyperbola curve?

[calena7178147]

The question states that the binding is not cooperative. Consider the classic model of cooperative/non-cooperative binding (Hemoglobin and Myoglobin)—they are proteins (not enzymes) that bind oxygen (substrate in enzyme models). Even though they are not enzymes, the principle is the same. Binding of oxygen to hemoglobin (blue curve) is cooperative. A sigmoidal curve is a characteristic of cooperative binding. After the first oxygen (like a substrate) molecule binds the second and third with much greater affinity. On the other hand, myoglobin (red curve) binds oxygen in a non-cooperative manner. Hyperbolic curves are characteristic of non-cooperative molecules. Once all of its sites are bound by oxygen(saturation point), then no more can bind. Remember the two bolded facts and you will not go wrong

[pinoalejan6739]

The sigmodial curve is the red one curve not the blue one. I don't know if am the one confused but it seems to me that if that the hyperbola curve is in blue which corresponds to cooperative binding.