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mashbour8199
Joined: 21 Jul 2009 Posts: 6
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Posted: Wed Aug 19, 2009 9:17 am Post subject: |
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Hi there!
The equation for H rxn is:
delta H rxn = product - reactants
and since these are the reaction pathways we see:
P(red) ---> CO2 (H= -2900 kJ/mol)
CO2 ---> P(white) (H= +3020 kJ/mol) (here, the sign is reversed from the one in the chart because we are looking at the formation of an oxide backwards)
Then shouldn't the final eqn be:
delta H rxn = 3020 - (-2900) = 5920?
That's the way I saw it, any suggestions/tips please? Thanks! |
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enachbe18198
Joined: 24 Feb 2010 Posts: 9
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Posted: Sun Mar 14, 2010 1:13 pm Post subject: Typo... |
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There's a typo here... the answer choice says +120 kJ/mol but in the explanation I see -120 kJ/mol. If I understand this correctly, I think the answer should be negative...
-3020 + 2900 = -120 .. can someone please clarify?  |
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mintzer_ja7368
Joined: 22 Feb 2010 Posts: 1
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Posted: Sun Mar 14, 2010 1:46 pm Post subject: |
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I think that the answer is +120 because:
Pred ---> Pox
Rxn = -2900
Pox ---> Pwhite
Rxn = 3200
And according to Hess's law, enthalpy changes of reactions are additive.
Thus Delta rxn = 3200 + -2900 = +120 kj/mol |
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enachbe18198
Joined: 24 Feb 2010 Posts: 9
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Posted: Mon Mar 15, 2010 11:30 am Post subject: |
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| Okay I see why I made my mistake.. thanks! |
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boshenliu34457
Joined: 20 Jul 2011 Posts: 8
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Posted: Wed Jul 27, 2011 10:23 pm Post subject: |
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| mintzer_ja7368 wrote: | I think that the answer is +120 because:
Pred ---> Pox
Rxn = -2900
Pox ---> Pwhite
Rxn = 3200
And according to Hess's law, enthalpy changes of reactions are additive.
Thus Delta rxn = 3200 + -2900 = +120 kj/mol |
shouldn't it be delta rxn = 3200 - (-2900) ? |
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