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behii208456
Joined: 14 Sep 2009
Posts: 8
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 Posted: Thu Oct 08, 2009 3:30 pm Post subject: |
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where does the ratio 4/5 come from?
if x=amplitude then that number should be 0.4
thank you |
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mcat_premed3832
Joined: 19 Oct 2006
Posts: 413
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| Posted: Tue Dec 22, 2009 11:43 am Post subject: |
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| The amplitude is 0.8 m (4/5) since the passage describes this is the value obtained by stretching. In other words, the string was simply "hanging" downward (equilibrium position) and then stretched to a maximum (amplitude) of 0.8 m. |
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dnpgr16513
Joined: 14 Jun 2010
Posts: 75
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| Posted: Tue Jun 29, 2010 2:12 pm Post subject: |
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Why wouldn't x be 2m since its the full length of the string? I thought when it asked for the PE before the mass was released the value would be 2 m.
thanks. |
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sbains3528
Joined: 16 Aug 2010
Posts: 14
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| Posted: Tue Aug 24, 2010 2:14 pm Post subject: |
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| I have the same question as the above poster. |
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miranda.li6606
Joined: 09 Jan 2011
Posts: 1
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| Posted: Fri Mar 18, 2011 2:25 pm Post subject: |
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You only include the distance from equilibrium position in the x term.
My question is why the stretching distance caused by the force of gravity was not taken into account. I assumed that the .8m the string was stretched was in addition to the stretching caused by the weight of the mass pulling it down. Can anyone explain why this isn't a factor? |
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