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jvuofm1709
Joined: 06 May 2010
Posts: 19
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 Posted: Tue May 18, 2010 3:01 am Post subject: |
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| ...The variables for this problem don't work for the ideal gas law. This problem should be changed so the equation actually works for different methods of calculation. P=3 atm V=50*5=250 mL= .250 L T=283 K R=.082 and n= 1 mol. 3*.250=1*.082*283 => .75=23.206 so either I'm making a huge mistake somewhere...or this problem needs to be changed. |
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jellywing_2058
Joined: 04 May 2009
Posts: 179
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| Posted: Tue Jun 01, 2010 2:02 pm Post subject: |
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You are absolutely right. The data is absolutely arbitrary. The only reason that the question worked out is because we don’t use this data.
The only things we need here are the Volume and Temperature. Pressure remains constant, and therefore even though it is erroneous, it doesn’t matter; it cancels out. |
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jsfkt78927
Joined: 06 Jul 2010
Posts: 44
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| Posted: Fri Aug 13, 2010 6:56 pm Post subject: |
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The problem is not that tricky if you substitute a variable in for A rather than using 50 cm^2. BUT, once again GS has included answer choices that are way too similar.
Once i get to 283(0.06)/0.05 , i should be able to round to at least to 280. This question is not like a typical MCAT question IMO. Try the math, if you round down to 280 what do you get... 356? yeah.... leads you to pick C.
Real MCAT would not discriminate between 283 x 0.06 and 280 x 0.06 |
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