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eo Guest
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Posted: Thu Mar 29, 2007 7:07 pm Post subject: Question 48 |
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| If you are traveling away from the police car then you would expect to have less frequency. So, wouldn't you subtract Vdetector from Vsound? |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2168
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Posted: Sat Mar 31, 2007 8:58 am Post subject: |
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Your logic is correct but the problem is your interpretation of the question.
The distance between the source (siren) and the observer/detector (you) is decreasing by 30 m/s (the police car is catching up). The sign convention for when the distance is decreasing: use +Vdetector and -V<sub>source</sub> (the opposite for when the distance is increasing).
NB This is a test question. Usually the doppler equation is provided on the MCAT then. of course, you need to know how to use it. |
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eo5 Guest
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Posted: Sun Apr 01, 2007 12:46 am Post subject: |
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I checked my other books and it says that if the detector is going away from the source you subtract the Vdector from V.....  |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2168
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Posted: Mon Apr 09, 2007 2:44 pm Post subject: |
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| We have said the same thing. Away is increasing, I gave the situation of "decreasing." |
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student Guest
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Posted: Thu Apr 12, 2007 9:36 pm Post subject: confused... |
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| I thought if you are moving away from the sound, it should be minus vdetector? positive v detector means you are going toward the sound (it says this in my other books as well) |
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admin Site Admin
Joined: 08 Dec 2003 Posts: 2168
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Posted: Fri Apr 13, 2007 9:19 am Post subject: |
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Yes, all correct.
Moving away from the source = distance increasing = negative Vdetector
Moving towards the source = distance decreasing = positive Vdetector
The calculation was done as though the detector is moving towards the source. Just as a reminder though: this was a test question so the score did not count towards your overall score.
Last edited by admin on Mon Jul 06, 2009 1:56 pm; edited 1 time in total |
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