| View previous topic :: View next topic |
| Author |
Message |
Guest
|
 Posted: Fri Apr 06, 2007 9:28 pm Post subject: Question 28 |
 |
|
| how did you get that value for x(max)? |
|
| Back to top |
|
 |
admin
Site Admin
Joined: 08 Dec 2003
Posts: 2168
|
| Posted: Fri Apr 06, 2007 9:49 pm Post subject: |
|
|
| The passage states that the system was stretched 20 cm or 20 x 10^-2 m from the equilibrium position. |
|
| Back to top |
|
|
jsfkt78927
Joined: 06 Jul 2010
Posts: 39
|
| Posted: Tue Jul 27, 2010 2:27 pm Post subject: |
|
|
Because the extra mass is added to the spring at maximum displacement, ie: KE=1/2mv^2 will equal zero.
why, because at maximum displacement the velocity has to be zero.
so remember your consevation of energy equation, E= KE + U
and your spring equations, KE= 1/2mv^2 ; U= 1/2k(delta)x^2.
KE becomes zero and the energy is thus equal to:
(1/2)(50)(4^-2)= 1J
Voila! |
|
| Back to top |
|
|
|
|
You can post new topics in this forum
You can reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum
|
|
FAQ
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
