Question 14

[mvenus9292913]

Methyl isobutyl ether has 5 carbons, doesn't it (4 carbons in the isobutyl group, and one in the methyl group). All of the choices, except for C should have 5 carbons, not 4.

Also, I'm officially confused with the names of the butyl groups. Regular butyl is -CH2-CH2-CH2-CH3, right? Isobutyl is -CH2-CH(CH3)2, isn't it? Tert-butyl is -C(CH3)3, and then sec-butyl is CH3-CH-CH2-CH3, with the other atom (oxygen in this case) bonded to the second carbon in the chain. If I'm wrong, please correct me.

[admin]

You are correct on all accounts!

Your description of regular (n), sec, iso and tert butyl are all correct.

You are also right about the 5 carbons and that is why 12 hydrogens make sense.

Compound C is C5H12O; in fact, in the passage, it says that Compound C is cleaved by HI to produce methyl iodide (a one carbon compound) and 2-butanol (a 4 carbon compound).

[admin]

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