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admin
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 Posted: Sun May 06, 2007 1:57 am Post subject: |
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You are correct on all accounts!
Your description of regular (n), sec, iso and tert butyl are all correct.
You are also right about the 5 carbons and that is why 12 hydrogens make sense.
Compound C is C5H12O; in fact, in the passage, it says that Compound C is cleaved by HI to produce methyl iodide (a one carbon compound) and 2-butanol (a 4 carbon compound). |
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admin
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| Posted: Thu Jul 30, 2009 3:52 pm Post subject: |
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