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GS-1 Biological Sciences Question 31

 
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vijkrishna3659



Joined: 23 Jun 2007
Posts: 2

PostPosted: Sat Jun 23, 2007 12:39 pm    Post subject: GS-1 Biological Sciences Question 31 Reply with quote

Sickle-cell anemia is a recessive trait.
According to the explanation, you are saying that a ss has no sickle-cell anemia, when in reality, ss means the person has anemia. Furthermore, SS or Ss would mean the person has regular hemoglobin. Ss is a carrier for the trait. Thus, when I did by crosses using this notation, I got the answer D. I don't understand why B. is correct and D. is wrong.
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admin
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Joined: 08 Dec 2003
Posts: 2176

PostPosted: Sat Jun 23, 2007 1:55 pm    Post subject: Reply with quote

Notation is up to you but that does not impact the answer. The Explanation used a different notation but that's OK, let's use yours (which is the classical way of doing it):

SS homozygous normal

Ss heterozygous, has the trait

ss homozygous thus has the disease

The cross, using your notation, in the second generation would then by SS x Ss. When you do the Punnett square you will get:

2 SS: 2 Ss

In other words, 1 normal : 1 sickle cell trait which is answer choice B.
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melissalyn4392



Joined: 24 Mar 2010
Posts: 1

PostPosted: Fri May 28, 2010 7:34 pm    Post subject: Reply with quote

If the heterozygous male in generation one (the square on the left) is replaced with a homozygous male for the normal condition; neither of the parents would have the trait. Therefore the male in the 2nd generation would also by homozygous. In the Punnett square explanation the parents are shown as one being Ss and one being ss. Shouldn't they be SS and ss?
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calena7178147



Joined: 26 Jan 2010
Posts: 44

PostPosted: Wed Jun 02, 2010 1:49 pm    Post subject: Reply with quote

The explanation in the book is correct. It may be confusing because the sickle cell disease is represented with SS (not ss); or you may be confused by which generation they are talking about. Here is the new pedigree with genotypes.



Therefore, crossing the second generation parents would be ss X Ss, as stated above. The Punnet square above is correct, and results in a 1:1 ratio of normal homozygous (ss) to heterozygous carriers (Ss).
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